输入: prices = [1, 3, 2, 8, 4, 9], fee = 2
输出: 8
解释: 能够达到的最大利润:
在此处买入 prices[0] = 1
在此处卖出 prices[3] = 8
在此处买入 prices[4] = 4
在此处卖出 prices[5] = 9
总利润: ((8 - 1) - 2) + ((9 - 4) - 2) = 8.
class Solution:
def maxProfit(self, prices: List[int], fee: int) -> int:
n = len(prices)
if n < 2:
return 0
hold, bear = -prices[0] - fee, 0
for i in range(1, n):
old_hold = hold
hold = max(old_hold, bear - prices[i] - fee)
bear = max(bear, old_hold + prices[i])
return bear